-16x^2+14x+380=0

Solution for -16x^2+14x+380=0 equation:

-16x^2+14x+380=0

a = -16; b = 14; c = +380;
Δ = b2-4ac
Δ = 142-4·(-16)·380
Δ = 24516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24516}=\sqrt{36*681}=\sqrt{36}*\sqrt{681}=6\sqrt{681}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-6\sqrt{681}}{2*-16}=\frac{-14-6\sqrt{681}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+6\sqrt{681}}{2*-16}=\frac{-14+6\sqrt{681}}{-32}
$